Solve the following equation. $\tan x - \sqrt { 3 } = 0$
A) $x = \frac { \pi } { 6 } + n \pi$ and $x = \frac { 5 \pi } { 6 } + n \pi$, where $n$ is an integer

B) $x = \frac { \pi } { 3 } + n \pi$, where $n$ is an integer

C) $x = \frac { \pi } { 4 } + n \pi$, where $n$ is an integer

D) $x = \frac { \pi } { 6 } + n \pi$, where $n$ is an integer

E) $x = \frac { 2 \pi } { 3 } + n \pi$ and $x = \frac { 4 \pi } { 3 } + n \pi$, where $n$ is an integer

Question

Solve the following equation. $\tan x - \sqrt { 3 } = 0$
A) $x = \frac { \pi } { 6 } + n \pi$ and $x = \frac { 5 \pi } { 6 } + n \pi$, where $n$ is an integer

B) $x = \frac { \pi } { 3 } + n \pi$, where $n$ is an integer

C) $x = \frac { \pi } { 4 } + n \pi$, where $n$ is an integer

D) $x = \frac { \pi } { 6 } + n \pi$, where $n$ is an integer

E) $x = \frac { 2 \pi } { 3 } + n \pi$ and $x = \frac { 4 \pi } { 3 } + n \pi$, where $n$ is an integer

Quizplus · Accepted Answer

The equation $\tan x = \sqrt{3}$ is satisfied when $x = \frac{\pi}{3} + n\pi$, because $\tan(\frac{\pi}{3}) = \sqrt{3}$ and the tangent function has a period of $\pi$.

Solve the Following Equation tan⁡x−3=0\tan x - \sqrt { 3 } = 0tanx−3​=0

Solve the Following Equation $\tan x - \sqrt { 3 } = 0$