Find $f \circ g$.
$$f ( x ) = x + 4 \quad g ( x ) = \frac { 3 } { x ^ { 2 } - 16 }$$
A) $( f \circ g ) ( x ) = \frac { 3 } { x ^ { 2 } }$
B) $( f \circ g ) ( x ) = \frac { 3 } { x ^ { 2 } + 8 x }$
C) $( f \circ g ) ( x ) = \frac { 4 x ^ { 2 } - 1 } { x ^ { 2 } - 16 }$
D) $( f \circ g ) ( x ) = \frac { 7 } { x ^ { 2 } - 16 }$
E) $( f \circ g ) ( x ) = \frac { 4 x ^ { 2 } - 61 } { x ^ { 2 } - 16 }$

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The Answer of Find $f \circ g$.
$$f ( x ) = x + 4 \quad g ( x ) = \frac { 3 } { x ^ { 2 } - 16 }$$
A) $( f \circ g ) ( x ) = \frac { 3 } { x ^ { 2 } }$
B) $( f \circ g ) ( x ) = \frac { 3 } { x ^ { 2 } + 8 x }$
C) $( f \circ g ) ( x ) = \frac { 4 x ^ { 2 } - 1 } { x ^ { 2 } - 16 }$
D) $( f \circ g ) ( x ) = \frac { 7 } { x ^ { 2 } - 16 }$
E) $( f \circ g ) ( x ) = \frac { 4 x ^ { 2 } - 61 } { x ^ { 2 } - 16 }$

Find f∘gf \circ gf∘g f(x)=x+4g(x)=3x2−16f ( x ) = x + 4 \quad g ( x ) = \frac { 3 } { x ^ { 2 } - 16 }f(x)=x+4g(x)=x2−163​

Find $f \circ g$ $f ( x ) = x + 4 \quad g ( x ) = \frac { 3 } { x ^ { 2 } - 16 }$