Given $f ( x ) = \frac { 10 } { x ^ { 2 } - 9 }$ and $g ( x ) = x + 3$ determine the domain of $f \circ g$.
A) $( - \infty , - 3 ) \cup ( 3 , \infty )$
B) $( - \infty , - 6 ) \cup ( - 6,0 ) \cup ( 0 , \infty )$
C) $\left( - \infty , - \frac { 10 } { 3 } \right) \cup \left( \frac { 10 } { 3 } , \infty \right)$
D) $( - \infty , - 3 ) \cup ( - 3,3 ) \cup ( 3 , \infty )$
E) $( - \infty , \infty )$

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The Answer of Given $f ( x ) = \frac { 10 } { x ^ { 2 } - 9 }$ and $g ( x ) = x + 3$ determine the domain of $f \circ g$.
A) $( - \infty , - 3 ) \cup ( 3 , \infty )$
B) $( - \infty , - 6 ) \cup ( - 6,0 ) \cup ( 0 , \infty )$
C) $\left( - \infty , - \frac { 10 } { 3 } \right) \cup \left( \frac { 10 } { 3 } , \infty \right)$
D) $( - \infty , - 3 ) \cup ( - 3,3 ) \cup ( 3 , \infty )$
E) $( - \infty , \infty )$

Given f(x)=10x2−9f ( x ) = \frac { 10 } { x ^ { 2 } - 9 }f(x)=x2−910​

Given $f ( x ) = \frac { 10 } { x ^ { 2 } - 9 }$