Find $f \circ g$
$$f ( x ) = x + 3 \quad g ( x ) = \frac { 4 } { x ^ { 2 } - 9 }$$
A) $( f \circ g ) ( x ) = \frac { 4 } { x ^ { 2 } }$
B) $( f \circ g ) ( x ) = \frac { 4 } { x ^ { 2 } + 6 x }$
C)
$( f \circ g ) ( x ) = \frac { 3 x ^ { 2 } + 1 } { x ^ { 2 } - 9 }$
D) $( f \circ g ) ( x ) = \frac { 7 } { x ^ { 2 } - 9 }$
E) $( f \circ g ) ( x ) = \frac { 3 x ^ { 2 } - 23 } { x ^ { 2 } - 9 }$

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The Answer of Find $f \circ g$
$$f ( x ) = x + 3 \quad g ( x ) = \frac { 4 } { x ^ { 2 } - 9 }$$
A) $( f \circ g ) ( x ) = \frac { 4 } { x ^ { 2 } }$
B) $( f \circ g ) ( x ) = \frac { 4 } { x ^ { 2 } + 6 x }$
C)
$( f \circ g ) ( x ) = \frac { 3 x ^ { 2 } + 1 } { x ^ { 2 } - 9 }$
D) $( f \circ g ) ( x ) = \frac { 7 } { x ^ { 2 } - 9 }$
E) $( f \circ g ) ( x ) = \frac { 3 x ^ { 2 } - 23 } { x ^ { 2 } - 9 }$

Find f∘gf \circ gf∘g f(x)=x+3g(x)=4x2−9f ( x ) = x + 3 \quad g ( x ) = \frac { 4 } { x ^ { 2 } - 9 }f(x)=x+3g(x)=x2−94​

Find $f \circ g$ $f ( x ) = x + 3 \quad g ( x ) = \frac { 4 } { x ^ { 2 } - 9 }$