Find all real values of $x$ such that $f ( x ) = 0$.
$$f ( x ) = \frac { - 3 x - 2 } { 5 }$$
A) $- \frac { 2 } { 15 }$
B) $\pm \frac { 2 } { 15 }$
C) $\pm \frac { 2 } { 3 }$
D) $- \frac { 2 } { 3 }$
E) $\frac { 2 } { 3 }$

Question

Quizplus · Accepted Answer

To find the real values of $x$ for which $f(x) = 0$, set the function equal to zero and solve for $x$:$$0 = \frac{-3x - 2}{5}$$Multiplying both sides by 5 to eliminate the denominator gives:$$0 = -3x - 2$$Adding 2 to both sides:$$2 = -3x$$Dividing both sides by -3:$$x = -\frac{2}{3}$$Therefore, the correct answer is $x = -\frac{2}{3}$, which corresponds to choice D.

Find All Real Values Of xxx Such That f(x)=0f ( x ) = 0f(x)=0

Find All Real Values Of $x$ Such That $f ( x ) = 0$