The function $f ( x ) = \sqrt { x ^ { 2 } - 6 }$ is one-to-one on the domain $x \leq - \sqrt { 6 }$. Find $f ^ { - 1 } ( x )$.
A) $f ^ { - 1 } ( x ) = - \sqrt { x ^ { 2 } - 6 }$
B) $\quad f ^ { - 1 } ( x ) = - \sqrt { x ^ { 2 } + 6 }$
C) $f ^ { - 1 } ( x ) = x ^ { 2 } + 6$
D) $f ^ { - 1 } ( x ) = \frac { 1 } { \sqrt { x ^ { 2 } - 6 } }$
E)
$$f ^ { - 1 } ( x ) = \sqrt { x ^ { 2 } + 6 }$$

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The Answer of The function $f ( x ) = \sqrt { x ^ { 2 } - 6 }$ is one-to-one on the domain $x \leq - \sqrt { 6 }$. Find $f ^ { - 1 } ( x )$.
A) $f ^ { - 1 } ( x ) = - \sqrt { x ^ { 2 } - 6 }$
B) $\quad f ^ { - 1 } ( x ) = - \sqrt { x ^ { 2 } + 6 }$
C) $f ^ { - 1 } ( x ) = x ^ { 2 } + 6$
D) $f ^ { - 1 } ( x ) = \frac { 1 } { \sqrt { x ^ { 2 } - 6 } }$
E)
$$f ^ { - 1 } ( x ) = \sqrt { x ^ { 2 } + 6 }$$

The Function f(x)=x2−6f ( x ) = \sqrt { x ^ { 2 } - 6 }f(x)=x2−6​

The Function $f ( x ) = \sqrt { x ^ { 2 } - 6 }$