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Question 50
Use the Quotient Rule to differentiate the function f(x) =8xx5+3. \text { Use the Quotient Rule to differentiate the function } f ( x ) = \frac { 8 x } { x ^ { 5 } + 3 } \text {. } Use the Quotient Rule to differentiate the function f(x) =x5+38x.
A) ft(x) =−8(−3+4x5) (x5+3) 2f ^ { t} ( x ) = - \frac { 8 \left( - 3 + 4 x ^ { 5 } \right) } { \left( x ^ { 5 } + 3 \right) ^ { 2 } }ft(x) =−(x5+3) 28(−3+4x5) B) ft(x) =8(−3−4x5) (x5+3) 2f ^ { t } ( x ) = \frac { 8 \left( - 3 - 4 x ^ { 5 } \right) } { \left( x ^ { 5 } + 3 \right) ^ { 2 } }ft(x) =(x5+3) 28(−3−4x5) C) ft(x) =−8(3+5x5) (x5+3) 2f ^ { t } ( x ) = - \frac { 8 \left( 3 + 5 x ^ { 5 } \right) } { \left( x ^ { 5 } + 3 \right) ^ { 2 } }ft(x) =−(x5+3) 28(3+5x5) D) ft(x) =8(3+4x5) (x5+3) 2f ^ { t } ( x ) = \frac { 8 \left( 3 + 4 x ^ { 5 } \right) } { \left( x ^ { 5 } + 3 \right) ^ { 2 } }ft(x) =(x5+3) 28(3+4x5) E) ft(x) =−8(3+6x5) (x5+3) 2f ^ { t } ( x ) = - \frac { 8 \left( 3 + 6 x ^ { 5 } \right) } { \left( x ^ { 5 } + 3 \right) ^ { 2 } }ft(x) =−(x5+3) 28(3+6x5)
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