$\text { Find } f ^ { - 1 } ( x ) \text { if } f ( x ) = 12 x - 10 \text {. }$
A) $f ^ { - 1 } ( x ) = \ln ( 12 x + 10 )$
B) $f ^ { - 1 } ( x ) = \frac { 1 } { 12 x - 10 }$
C) $f ^ { - 1 } ( x ) = \frac { 1 } { 12 } x + \frac { 1 } { 10 }$
D) $f ^ { - 1 } ( x ) = 10 x - 12$
E) $f ^ { - 1 } ( x ) = \frac { 1 } { 12 } x + \frac { 5 } { 6 }$

Question

$\text { Find } f ^ { - 1 } ( x ) \text { if } f ( x ) = 12 x - 10 \text {. }$ 
A) $f ^ { - 1 } ( x ) = \ln ( 12 x + 10 )$
B) $f ^ { - 1 } ( x ) = \frac { 1 } { 12 x - 10 }$
C) $f ^ { - 1 } ( x ) = \frac { 1 } { 12 } x + \frac { 1 } { 10 }$
D) $f ^ { - 1 } ( x ) = 10 x - 12$
E) $f ^ { - 1 } ( x ) = \frac { 1 } { 12 } x + \frac { 5 } { 6 }$

Quizplus · Accepted Answer

The Answer of $\text { Find } f ^ { - 1 } ( x ) \text { if } f ( x ) = 12 x - 10 \text {. }$ 
A) $f ^ { - 1 } ( x ) = \ln ( 12 x + 10 )$
B) $f ^ { - 1 } ( x ) = \frac { 1 } { 12 x - 10 }$
C) $f ^ { - 1 } ( x ) = \frac { 1 } { 12 } x + \frac { 1 } { 10 }$
D) $f ^ { - 1 } ( x ) = 10 x - 12$
E) $f ^ { - 1 } ( x ) = \frac { 1 } { 12 } x + \frac { 5 } { 6 }$

Find f−1(x) if f(x)=12x−10. \text { Find } f ^ { - 1 } ( x ) \text { if } f ( x ) = 12 x - 10 \text {. } Find f−1(x) if f(x)=12x−10.

$\text { Find } f ^ { - 1 } ( x ) \text { if } f ( x ) = 12 x - 10 \text {. }$