Calculate the pressure amplitude (in N/m²) of a 500 Hz sound wave in helium if the displacement amplitude is equal to 5.0 *10-8 m. ($\rho$ = 0.179 kg/m3, v = 972 m/s.) A)3.5* 10-2 B)1.6 *10-2 C)2.7 * 10-2 D)4.2 * 10-2 E)2.0 *10-2

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Quizplus · Accepted Answer

The pressure amplitude (Pa) of a sound wave can be calculated using the equation: Pa = ρvωA where ρ is the density of the medium (0.179 kg/m3 for helium), v is the speed of sound in the medium (972 m/s for helium), ω is the angular frequency (2πf), f is the frequency in Hz (500 Hz in this case), and A is the displacement amplitude (5.0 × 10-8 m in this case). Using the given values, we get: ω = 2πf = 2π × 500 = 1000π rad/s Pa = ρvωA = 0.179 × 972 × 1000π × 5.0 × 10-8 = 2.7 × 10-2 N/m2 = 2.7 F1F1F1S1F1F1F10 10F1F1F1S1F1F1F102 N/m² Therefore, the correct choice is C.

Calculate the Pressure Amplitude (In N/m2) of a 500 Hz ρ\rhoρ

Calculate the Pressure Amplitude (In N/m²) of a 500 Hz $\rho$