A delta-connected alternator is connected to a wye-connected resistive load. The alternator produces a line voltage of 240V, and the resistors have a value of 6 ohm each. Using Ohm's law, we determine the amount of phase current, IP(Load) = ____A.
A) 13.3
B) 23.1
C) 26.6
D) 69.28

Question

Quizplus · Accepted Answer

In a wye-connected load, the phase voltage is the line voltage divided by √3. Thus, the phase voltage is 240V/√3 = 138.56V. Using Ohm's law, the phase current is 138.56V / 6Ω = 23.1A.

A Delta-Connected Alternator Is Connected to a Wye-Connected Resistive Load