What volume of 0.10 M NaOH can be prepared from 250. mL of 0.30 M NaOH?
A)750 L
B)0.75 L
C)0.25 L
D)0.075 L
E)0.083 L

Question

Quizplus · Accepted Answer

To prepare a solution of lower concentration from a higher concentration, the formula $C_1V_1 = C_2V_2$ is used, where $C_1$ and $V_1$ are the concentration and volume of the initial solution, and $C_2$ and $V_2$ are the concentration and volume of the final solution, respectively. Plugging in the given values: $0.30 \, \text{M} \times 250 \, \text{mL} = 0.10 \, \text{M} \times V_2$. Solving for $V_2$ gives $V_2 = 750 \, \text{mL}$ or $0.75 \, \text{L}$.

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