Find two functions defined implicitly by the given relation.
-$3 x ^ { 2 } - y ^ { 2 } = 4$
A) $y = \frac { x \sqrt { 3 } } { 2 }$ or $y = - \frac { x \sqrt { 3 } } { 2 }$
B) $y = \sqrt { 3 } x - \sqrt { 4 }$ or $y = - \sqrt { 3 } x + \sqrt { 4 }$
C) $y = \sqrt { 3 x ^ { 2 } - 4 }$ or $y = \sqrt { 3 x ^ { 2 } + 4 }$
D) $y = \sqrt { 3 x ^ { 2 } - 4 }$ or $y = - \sqrt { 3 x ^ { 2 } - 4 }$

Question

Quizplus · Accepted Answer

Solving the given relation $3x^2 - y^2 = 4$ for $y$ gives two functions: $y = \sqrt{3x^2 - 4}$ and $y = -\sqrt{3x^2 - 4}$, representing the positive and negative square roots, respectively.

Find Two Functions Defined Implicitly by the Given Relation 3x2−y2=43 x ^ { 2 } - y ^ { 2 } = 43x2−y2=4

Find Two Functions Defined Implicitly by the Given Relation $3 x ^ { 2 } - y ^ { 2 } = 4$