Find the asymptote(s) of the given function.
-$g ( x ) = \frac { x ^ { 2 } + 1 x - 3 } { x - 3 }$ horizontal asymptotes(s)
A) $y = - 1$
B) None
C) $\mathrm { y } = 3$
D) $\mathrm { y } = 9$

Question

Quizplus · Accepted Answer

Horizontal asymptotes are found by comparing the degrees of the polynomial in the numerator and the denominator. In this case, the degree of the numerator (2) is higher than the degree of the denominator (1), which means there are no horizontal asymptotes.

Find the Asymptote(s) of the Given Function g(x)=x2+1x−3x−3g ( x ) = \frac { x ^ { 2 } + 1 x - 3 } { x - 3 }g(x)=x−3x2+1x−3​

Find the Asymptote(s) of the Given Function $g ( x ) = \frac { x ^ { 2 } + 1 x - 3 } { x - 3 }$