Find the asymptote(s) of the given function.
-$f ( x ) = \frac { x - 3 } { x ^ { 2 } - 36 }$ vertical asymptotes(s)
A) $x = - 6$
B) $x = 3$
C) $x = 6 , x = - 6$
D) $x = 6$

Question

Quizplus · Accepted Answer

Vertical asymptotes occur where the denominator of a rational function is zero (and the numerator is not zero at those points). For $f(x) = \frac{x - 3}{x^2 - 36}$, the denominator is $x^2 - 36 = (x - 6)(x + 6)$, which is zero at $x = 6$ and $x = -6$.

Find the Asymptote(s) of the Given Function f(x)=x−3x2−36f ( x ) = \frac { x - 3 } { x ^ { 2 } - 36 }f(x)=x2−36x−3​

Find the Asymptote(s) of the Given Function $f ( x ) = \frac { x - 3 } { x ^ { 2 } - 36 }$