Solve the problem.
-A plane suddenly experiences turbulence while in flight. At this point the change in its altitude, in feet, is represt the following function of time:
$$F ( t ) = \frac { 5 ( t - 10 ) ^ { 2 } - 19 } { 20 ( t - 10 ) ^ { 2 } - 10 ( t - 10 ) + 16 }$$
Assuming that the turbulence first hits at time $t = 0$, what is the maximum relative drop the plane will experienc due to turbulence? (Round the result to the nearest hundredth.)
A) $0.25 \mathrm { ft }$.
B) $28.19 \mathrm { ft }$.
C) $1.27 \mathrm { ft }$.
D) $10.21 \mathrm { ft }$.

Question

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The Answer of Solve the problem.
-A plane suddenly experiences turbulence while in flight. At this point the change in its altitude, in feet, is represt the following function of time:
$$F ( t ) = \frac { 5 ( t - 10 ) ^ { 2 } - 19 } { 20 ( t - 10 ) ^ { 2 } - 10 ( t - 10 ) + 16 }$$
Assuming that the turbulence first hits at time $t = 0$, what is the maximum relative drop the plane will experienc due to turbulence? (Round the result to the nearest hundredth.)
A) $0.25 \mathrm { ft }$.
B) $28.19 \mathrm { ft }$.
C) $1.27 \mathrm { ft }$.
D) $10.21 \mathrm { ft }$.

Solve the Problem F(t)=5(t−10)2−1920(t−10)2−10(t−10)+16F ( t ) = \frac { 5 ( t - 10 ) ^ { 2 } - 19 } { 20 ( t - 10 ) ^ { 2 } - 10 ( t - 10 ) + 16 }F(t)=20(t−10)2−10(t−10)+165(t−10)2−19​

Solve the Problem $F ( t ) = \frac { 5 ( t - 10 ) ^ { 2 } - 19 } { 20 ( t - 10 ) ^ { 2 } - 10 ( t - 10 ) + 16 }$