Find the axis of the graph of the function.
-$$f ( x ) = 4 x ^ { 2 } + 32 x + 65$$
A) $x = 0$
B) $x = 5$
C) $x = 1$
D) $x = - 4$

Name: Find the axis of the graph of the function. -\[f ( x ) = 4 x ^ { 2 } + 32 x + 65\] A) $x = 0$ B) $x = 5$ C) $x = 1$ D) $x = - 4$
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Question

Quizplus · Accepted Answer

The axis of symmetry for a quadratic function $f(x) = ax^2 + bx + c$ is given by $x = -\frac{b}{2a}$. For $f(x) = 4x^2 + 32x + 65$, $a = 4$ and $b = 32$. Thus, the axis is $x = -\frac{32}{2 \times 4} = -4$.

Find the Axis of the Graph of the Function f(x)=4x2+32x+65f ( x ) = 4 x ^ { 2 } + 32 x + 65f(x)=4x2+32x+65

Find the Axis of the Graph of the Function $f ( x ) = 4 x ^ { 2 } + 32 x + 65$