Solve the problem.
-A certain noise produces $1.49 \times 10 ^ { - 5 } \mathrm { Watts } / \mathrm { m } ^ { 2 }$ of power. What is the decibel level of this noise? The level of sound intensity in decibels $( \mathrm { dB } )$ is $\beta = 10 \log \left( \mathrm { I } / \mathrm { I } _ { 0 } \right)$, where $\beta$ (beta) is the number of decibels, I is the sound intensity in $\mathrm { W } / \mathrm { m } ^ { 2 }$, and $\mathrm { I } _ { 0 } = 10 ^ { - 12 } \mathrm {~W} / \mathrm { m } ^ { 2 }$. (Round to the nearest decibel.)
A) 165 decibels
B) 62 decibels
C) 72 decibels
D) 7 decibels

Question

Quizplus · Accepted Answer

The decibel level is calculated as $\beta = 10 \log \left( \frac{1.49 \times 10^{-5}}{10^{-12}} \right)$. This simplifies to $\beta = 10 \log (1.49 \times 10^7)$. Calculating this gives approximately 72 decibels.

Solve the Problem 1.49×10−5Watts/m21.49 \times 10 ^ { - 5 } \mathrm { Watts } / \mathrm { m } ^ { 2 }1.49×10−5Watts/m2

Solve the Problem $1.49 \times 10 ^ { - 5 } \mathrm { Watts } / \mathrm { m } ^ { 2 }$