Solve the Problem $/ \mathrm { m } ^ { 2 }$

Solve the problem.
-What is the intensity in Watts $/ \mathrm { m } ^ { 2 }$ of a noise measured at 70 decibels? The level of sound intensity in decibels (dB) is $\beta = 10 \log \left( \frac { \mathrm { I } } { \mathrm { I } } \right)$ , where $\beta$ (beta) is the number of decibels, I is the sound intensity in $W / \mathrm { m } ^ { 2 }$ , and $\mathrm { I } _ { 0 } = 10 ^ { - 12 } \mathrm {~W} / \mathrm { m } ^ { 2 }$ . (Round to the nearest decibel.)

A) $1.00 \times 10 ^ { - 4 } \mathrm {~W} / \mathrm { m } ^ { 2 }$
B) $1.10 \times 1015 \mathrm {~W} / \mathrm { m } ^ { 2 }$
C) $7.00 \times 10 ^ { - 10 } \mathrm {~W} / \mathrm { m } ^ { 2 }$
D) $1.00 \times 10 ^ { - 5 } \mathrm {~W} / \mathrm { m } ^ { 2 }$