Solve the problem.
-Suppose the amount of a radioactive element remaining in a sample of 100 milligrams after x years can be described by $A ( x ) = 100 \mathrm { e } ^ { - 0.01828 x }$. How much is remaining after 50 years? Round the answer to the nearest hundredth of a milligram.
A) $91.40$ milligrams
B) $249.43$ milligrams
C) $0.40$ milligrams
D) $40.09$ milligrams

Question

Quizplus · Accepted Answer

To find the amount remaining after 50 years, substitute $x = 50$ into the given formula: $A(50) = 100e^{-0.01828 \times 50}$. Calculating this gives approximately $40.09$ milligrams.

Solve the Problem A(x)=100e−0.01828xA ( x ) = 100 \mathrm { e } ^ { - 0.01828 x }A(x)=100e−0.01828x

Solve the Problem $A ( x ) = 100 \mathrm { e } ^ { - 0.01828 x }$