Solve the triangle.
-$$\mathrm { a } = 3 , \mathrm {~b} = 11 , \mathrm { c } = 6$$
A) No triangles possible
B) $\mathrm { A } \approx 31.8 ^ { \circ } , \mathrm { B } \approx 63.6 ^ { \circ } , \mathrm { C } \approx 84.6 ^ { \circ }$
C) $\mathrm { A } \approx 63.6 ^ { \circ } , \mathrm { B } \approx 84.6 ^ { \circ } , \mathrm { C } \approx 11 ^ { \circ }$
D) $\mathrm { A } \approx 31.8 ^ { \circ } , \mathrm { B } \approx 43.9 ^ { \circ } , \mathrm { C } \approx 104.3 ^ { \circ }$

Question

Quizplus · Accepted Answer

The given side lengths do not satisfy the triangle inequality theorem, which states that the sum of the lengths of any two sides must be greater than the length of the remaining side. Here, 3 + 6 is not greater than 11.

Solve the Triangle a=3, b=11,c=6\mathrm { a } = 3 , \mathrm {~b} = 11 , \mathrm { c } = 6a=3, b=11,c=6

Solve the Triangle $\mathrm { a } = 3 , \mathrm {~b} = 11 , \mathrm { c } = 6$