Find the magnitude and direction angle for the following vector. Give the direction angle as an angle in [0°, 360°) rounded to the nearest tenth.
-$3 \left( \cos 102 ^ { \circ } \mathbf { i } + \sin 102 ^ { \circ } \mathbf { j } \right)$
A) $\sqrt { 3 } , 102 ^ { \circ }$
B) $3,78 ^ { \circ }$
C) $9,78 ^ { \circ }$
D) $3,102 ^ { \circ }$

Question

Quizplus · Accepted Answer

The magnitude of the vector is 3, and the direction angle is given directly as $102^\circ$, which is already in the desired range $[0^\circ, 360^\circ)$.

Find the Magnitude and Direction Angle for the Following Vector 3(cos⁡102∘i+sin⁡102∘j)3 \left( \cos 102 ^ { \circ } \mathbf { i } + \sin 102 ^ { \circ } \mathbf { j } \right)3(cos102∘i+sin102∘j)

Find the Magnitude and Direction Angle for the Following Vector $3 \left( \cos 102 ^ { \circ } \mathbf { i } + \sin 102 ^ { \circ } \mathbf { j } \right)$