Solve.
-A collection of dimes is arranged in a triangular array with 17 coins in the base row, 16 in the next, 15 in the next, and so forth with 1 dime in the last row. Find the value of the collection.
A) $\$ 7.65$
B) $\$ 1.53$
C) $\$ 30.60$
D) $\$ 15.30$

Question

Quizplus · Accepted Answer

The value of the collection can be found by first determining the total number of dimes in the triangular array. This is a sum of an arithmetic series with the first term $a_1 = 17$, the last term $a_n = 1$, and the number of terms $n = 17$. The sum $S$ of the first $n$ terms of an arithmetic series is given by $S = \frac{n}{2}(a_1 + a_n)$. Substituting the given values, we get $S = \frac{17}{2}(17 + 1) = \frac{17}{2} \times 18 = 153$. Since each dime is worth $0.10, the total value of the collection is $153 \times 0.10 = \$15.30$.

Solve -A Collection of Dimes Is Arranged in a Triangular $7.65\$ 7.65$7.65

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-A Collection of Dimes Is Arranged in a Triangular $\$ 7.65$