Write the product in standard form.
-$( \sqrt { 6 } - 3 i ) ( \sqrt { 6 } + 3 i )$
A) $6 + 9 i$
B) $6 - 9 i$
C) 9
D) 15

Name: Write the product in standard form. -$( \sqrt { 6 } - 3 i ) ( \sqrt { 6 } + 3 i )$ A) $6 + 9 i$ B) $6 - 9 i$ C) 9 D) 15
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Question

Quizplus · Accepted Answer

Using the formula for the product of conjugates, $(a - bi)(a + bi) = a^2 + b^2$, where $a = \sqrt{6}$ and $b = 3$, the product is $(\sqrt{6})^2 + (3)^2 = 6 + 9 = 15$.

Write the Product in Standard Form (6−3i)(6+3i)( \sqrt { 6 } - 3 i ) ( \sqrt { 6 } + 3 i )(6​−3i)(6​+3i)

Write the Product in Standard Form $( \sqrt { 6 } - 3 i ) ( \sqrt { 6 } + 3 i )$