Calculate the result to four decimal places given r = 1.3 and t = 2.6 $\frac{5 r^{6} t^{8}}{\left(7 r^{2} t\right)^{4}}$
A) 1.0683
B) .0563
C) .0885
D) 1.2573
E) 6.2675

Question

Quizplus · Accepted Answer

First, simplify the expression: $\frac{5 r^{6} t^{8}}{\left(7 r^{2} t\right)^{4}} = \frac{5 r^{6} t^{8}}{7^4 r^{8} t^4}$. This simplifies to $\frac{5 t^4}{7^4 r^2}$. Substitute $r = 1.3$ and $t = 2.6$ into the expression and calculate: $\frac{5 \times (2.6)^4}{(7^4) \times (1.3)^2} = \frac{5 \times 456.976}{2401 \times 1.69} = \frac{2284.88}{4056.69} \approx 0.0563$.

Calculate the Result to Four Decimal Places Given R = 5r6t8(7r2t)4\frac{5 r^{6} t^{8}}{\left(7 r^{2} t\right)^{4}}(7r2t)45r6t8​

Calculate the Result to Four Decimal Places Given R = $\frac{5 r^{6} t^{8}}{\left(7 r^{2} t\right)^{4}}$