Calculate the final result to two decimal places, where z = .1515 $\frac{z}{4}+z^{4}+\frac{7}{9}-.25 z^{2}+\frac{2}{3}$
A) .48
B) 2.65
C) 1.48
D) 3.22
E) 5.48

Question

Quizplus · Accepted Answer

First, calculate each term with z = .1515:- $\frac{z}{4} = \frac{.1515}{4} = .037875$- $z^{4} = (.1515)^{4} = .000053034$- $\frac{7}{9} = .777777...$- $-.25z^{2} = -.25(.1515)^{2} = -.25(.02295225) = -.005738$- $\frac{2}{3} = .666666...$Adding these together:.037875 + .000053034 + .777777 - .005738 + .666666 = 1.476633034Rounded to two decimal places, the final result is 1.48.

Calculate the Final Result to Two Decimal Places, Where Z z4+z4+79−.25z2+23\frac{z}{4}+z^{4}+\frac{7}{9}-.25 z^{2}+\frac{2}{3}4z​+z4+97​−.25z2+32​

Calculate the Final Result to Two Decimal Places, Where Z $\frac{z}{4}+z^{4}+\frac{7}{9}-.25 z^{2}+\frac{2}{3}$