Use the data given below to answer the following question(s).
In an event $ X $, the probability of rolling a sum of 8 on two dice is $ \frac{5}{36} $ while the probability of rolling an 11 is $ \frac{2}{36} $. In another event $ Y $, the probability of rolling a 2 is $ \frac{1}{36} $, the probability of rolling a 9 is $ \frac{4}{36} $, and the probability of rolling a 4 is $ \frac{3}{36} $.
-Consider an event Z that includes all outcomes of rolling two dice whose sum is odd.What is the probability that either event Y or Z occurs?
A)$\frac{26}{36}$

B)$\frac{22}{36}$

C)$\frac{10}{36}$

D)$\frac{18}{36}$

Question

Use the data given below to answer the following question(s).
In an event $ X $, the probability of rolling a sum of 8 on two dice is $ \frac{5}{36} $ while the probability of rolling an 11 is $ \frac{2}{36} $. In another event $ Y $, the probability of rolling a 2 is $ \frac{1}{36} $, the probability of rolling a 9 is $ \frac{4}{36} $, and the probability of rolling a 4 is $ \frac{3}{36} $. 
-Consider an event Z that includes all outcomes of rolling two dice whose sum is odd.What is the probability that either event Y or Z occurs?
A)$\frac{26}{36}$

B)$\frac{22}{36}$

C)$\frac{10}{36}$

D)$\frac{18}{36}$

Quizplus · Accepted Answer

The probability of Z is equal to the probability of getting an odd sum. We can calculate this by subtracting the probability of getting an even sum from 1. The probability of getting an even sum is the sum of the probabilities of rolling a 2, 4, 6, 8, 10, or 12, which is $ \frac{1}{36} + \frac{3}{36} + \frac{5}{36} + \frac{5}{36} + \frac{3}{36} + \frac{1}{36} = \frac{18}{36} $. So, the probability of Z is $ 1 - \frac{18}{36} = \frac{18}{36} $.
Therefore, the probability of either event Y or Z occurring is $ \frac{4}{36} + \frac{18}{36} = \frac{22}{36} $. So, the best choice is B.

Use the Data Given Below to Answer the Following Question(s) X X X

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