What is ΔH°_rxn for the reaction 2Al₂O₃(s) → 4Al(s) + 3O₂(g)? ΔH°_f(Al₂O₃(s)) = -1670 kJ/mol A) 3340 kJ/mol B) 1670 kJ/mol C) -3340 kJ/mol D) -1670 kJ/mol E) -835 kJ/mol

Question

Quizplus · Accepted Answer

The ΔH°_rxn for the reaction can be calculated using the ΔH°_f values of the reactants and products:ΔH°_rxn = ΣΔH°_f(products) - ΣΔH°_f(reactants)ΔH°_rxn = [4ΔH°_f(Al(s)) + 3ΔH°_f(O₂(g))] - [2ΔH°_f(Al₂O₃(s))]ΔH°_rxn = [4(0 kJ/mol) + 3(0 kJ/mol)] - [2(-1670 kJ/mol)]ΔH°_rxn = 3340 kJ/mol

What Is ΔH°rxn for the Reaction 2Al2O3(s) → 4Al(s)

What Is ΔH°_rxn for the Reaction 2Al₂O₃(s) → 4Al(s)