The reaction SiO₂(s) + Pb(s) → PbO₂(s) + Si(s) is spontaneous:
ΔG°_f (PbO₂(s)) = -217 kJ/mol
ΔG°_f (SiO₂(s)) = -856 kJ/mol

Question

The reaction SiO₂(s) + Pb(s) → PbO₂(s) + Si(s) is spontaneous: ΔG°_f (PbO₂(s)) = -217 kJ/mol ΔG°_f (SiO₂(s)) = -856 kJ/mol

Quizplus · Accepted Answer

The spontaneity of a reaction is determined by the sign of the Gibbs free energy change (ΔG°) for the reaction. If ΔG° is negative, the reaction is spontaneous. The given ΔG°f values alone do not determine the spontaneity of the reaction without considering the entire reaction's Gibbs free energy change, which involves all reactants and products.

The Reaction SiO2(s) + Pb(s) → PbO2(s) + Si(s) Is

The Reaction SiO₂(s) + Pb(s) → PbO₂(s) + Si(s) Is