In the complex ion [Fe(CN)₆]^4-, what is the oxidation number of Fe? A) +1 B) +2 C) +3 D) -4 E) +6

Question

Quizplus · Accepted Answer

The oxidation number of cyanide is -1 and the oxidation number of sulfur in thiosulfate ion (S2O32-) is +2. There are two cyanide ligands and one thiosulfate ligand in the complex ion. Therefore, the total charge contributed by ligands is -3 (2 x (-1) + 1 x (+2)). The overall charge of the complex ion is -1. Therefore, the oxidation number of Fe can be calculated as follows:

Fe + (-3) = -1

Fe = +2

Therefore, the oxidation number of Fe in the complex ion is +2.

In the Complex Ion [Fe(CN)6]4-, What Is the Oxidation Number

In the Complex Ion [Fe(CN)₆]^4-, What Is the Oxidation Number