Let z be a normal random variable with mean ($\mu$)0 and standard deviation ()of 1.What is P(z -1.1)?
A)0.36432
B)0.8643
C)0.1357
D)-0.1357
E)-0.8643

Question

Let z be a normal random variable with mean ($\mu$)0 and standard deviation ()of 1.What is P(z > -1.1)?
A)0.36432
B)0.8643
C)0.1357
D)-0.1357
E)-0.8643

Quizplus · Accepted Answer

The standard normal distribution table or a calculator shows that P(z > -1.1) is 0.8643. This is because the cumulative probability P(z ≤ -1.1) is 0.1357, and thus P(z > -1.1) = 1 - 0.1357 = 0.8643.

Let Z Be a Normal Random Variable with Mean μ\muμ )0 and Standard Deviation ()Of 1

Let Z Be a Normal Random Variable with Mean $\mu$ )0 and Standard Deviation ()Of 1