For the following ANOVA table, the df_Error value is ___. A)4 B)20 C)12 D)64 E)16

Question

Quizplus · Accepted Answer

For ANOVA table, df_Error denotes the degrees of freedom within the groups, which is equal to (number of groups - 1) times (number of observations per group - 1). In this case, we can see that there is only one group (B0U1S1) with 5 observations, so the degrees of freedom within this group would be (1-1)*(5-1) = 0. Similarly, there is only one group (B1U1S1) with 6 observations, so the degrees of freedom within this group would be (1-1)*(6-1) = 0. Thus, the only source of variation left to calculate is the error term, which is calculated as the total degrees of freedom minus the sum of the other sources of variation (in this case, the total degrees of freedom is 29 - see the "df" column in the ANOVA table). Therefore, the degrees of freedom for the error term would be 29 - 0 - 0 = 29, and since there are 2 treatments (B0U1S1 and B1U1S1), the total degrees of freedom for the F-test would be 29 - 2 = 27. Using this reasoning, we can see that the value given in the question stem (df_Error) corresponds to the degrees of freedom for the error term, which is equal to (number of observations - number of groups) = (5 + 6) - 2 = 9 - 2 = 7. Since there is one factor (B1U1S1) with two levels, we can also calculate the degrees of freedom for this factor as (number of levels - 1) = 1. Therefore, the ANOVA table would have the following degrees of freedom: Source | df ----------------|----- B1U1S1 | 1 Error | 7 Total | 8 Note that the value given in the question stem (df_Error = 20) does not correspond to any of these degrees of freedom, and in fact is not plausible given the sample sizes and number of groups provided in the table.

For the Following ANOVA Table, the DfError Value Is ___

For the Following ANOVA Table, the Df_Error Value Is ___