Uncertainty principle using ΔEΔt ≥ ħ/2: The excited state of a certain atom is 3.2 eV ±0.21 eV. ( ħ = 1.055 × 10^-34 J ∙ s = 6.591 × 10^-16 eV ∙ s, 1 eV = 1.60 × 10^-19 J)
(a) What is the average lifetime of this state?
(b) If the excited energy were doubled to 6.4 eV ± 0.21 eV, how would the lifetime be affected?

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The Answer of Uncertainty principle using ΔEΔt ≥ ħ/2: The excited state of a certain atom is 3.2 eV ±0.21 eV. ( ħ = 1.055 × 10^-34 J ∙ s = 6.591 × 10^-16 eV ∙ s, 1 eV = 1.60 × 10^-19 J) (a) What is the average lifetime of this state? (b) If the excited energy were doubled to 6.4 eV ± 0.21 eV, how would the lifetime be affected?

Uncertainty Principle Using ΔEΔt ≥ ħ/2: the Excited State of a Certain