Rotational dynamics about a moving axis: A uniform solid cylindrical log begins rolling without slipping down a ramp that rises 28.0° above the horizontal. After it has rolled 4.20 m along the ramp, what is the magnitude of the linear acceleration of its center of mass? A) 9.80 m/s² B) 4.60 m/s² C) 3.29 m/s² D) 3.07 m/s² E) 2.30 m/s²

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Quizplus · Accepted Answer

The linear acceleration of the center of mass is given by a = g*sin(theta), where g is the acceleration due to gravity and theta is the angle of the ramp. In this case, theta = 28.0°, so a = (9.80 m/s^2)*sin(28.0°) = 4.60 m/s^2.

Rotational Dynamics About a Moving Axis: a Uniform Solid Cylindrical