Two solenoids of equal length are each made of 2000 turns of copper wire per meter. Solenoid I has a 5.00 cm radius; solenoid II a 10.0 cm radius. When equal currents are present in the two solenoids, the ratio of the magnitude of the magnetic field B_I along the axis of solenoid I to the magnitude of the magnetic field B_II along the axis of solenoid II, B_I/B_II, is A) 1/4. B) 1/2. C) 1. D) 2. E) 4.

Question

Quizplus · Accepted Answer

The magnetic field inside a long solenoid is given by the formula B = μ₀nI, where μ₀ is the permeability of free space, n is the number of turns per unit length, and I is the current. Since both solenoids have the same number of turns per meter and the same current, the magnetic field strength inside each solenoid will be the same, regardless of their radii. Therefore, the ratio of the magnetic fields is 1.

Two Solenoids of Equal Length Are Each Made of 2000