Glucose is labeled with radioactive 14C and followed as it is oxidized to CO₂ and H₂0 in a mammalian liver cell. During this process the radioactive labeling will be detectable in? A) mitochondria only B) first in the nucleus, then in the mitochondria C) first in the mitochondria then on the ribosomes D) first in the cytoplasm then in the mitochondria

Question

Quizplus · Accepted Answer

Glucose is oxidized to pyruvate in the cytoplasm through glycolysis, where a small amount of energy is produced. Pyruvate then enters the mitochondria, where it undergoes the process of oxidative phosphorylation to produce a large amount of energy in the form of ATP. Therefore, the radioactive labeling will first be detectable in the cytoplasm during glycolysis, and then in the mitochondria during oxidative phosphorylation. It will not be detectable in the nucleus or on the ribosomes.

Glucose Is Labeled with Radioactive 14C and Followed as It