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A man who is an achondroplastic dwarf with normal vision marries a color-blind woman of normal height. The man's father was 6 feet tall, and both the woman's parents were of average height. Achondroplastic dwarfism is autosomal dominant, and red-green color blindness is X-linked recessive.
-How many of their daughters might be expected to be color-blind dwarfs?
A) all
B) none
C) half
D) one out of four
E) three out of four

Question

Quizplus · Accepted Answer

Since achondroplastic dwarfism is autosomal dominant, the man must have one allele for dwarfism and one for normal height. The woman, having normal height, can only contribute alleles for normal height. For color blindness, which is X-linked recessive, the woman must have two alleles for color blindness (being color-blind herself), and she can only pass on the color-blind allele to her children. However, since the man has normal vision, his X chromosome does not carry the allele for color blindness. Daughters receive one X chromosome from each parent. Thus, all daughters will receive the X chromosome with normal vision from their father and the X chromosome with color blindness from their mother, making them carriers but not color-blind. Additionally, since the father has one allele for dwarfism, there is a 50% chance for each child to inherit dwarfism, but this does not affect the calculation for color blindness directly. Therefore, none of their daughters would be color-blind dwarfs.

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