Balance the following equation: C₈H₁₈O₃(l) + O₂(g) → H₂O(g) + CO₂(g) A)C ₈H ₁₈O ₃( l)+ 8O ₂( g)→ 9H ₂O( g)+ 8CO ₂( g) B)C ₈H ₁₈O ₃( l)+ 11O ₂( g)→ 9H ₂O( g)+ 8CO ₂( g) C)2C ₈H ₁₈O ₃( l)+ 22O ₂( g)→ 9H ₂O( g)+ 16CO ₂( g) D)C ₈H ₁₈O ₃( l)+ 13O ₂( g)→ 18H ₂O( g)+ 8CO ₂( g) E)2C ₈H ₁8O ₃( l)+ 17O ₂( g)→ 18H ₂O( g)+ 16CO ₂( g)

Question

Quizplus · Accepted Answer

First of all, count the number of atoms on both sides of the equation: Reactants: C1₈H1₁₈O1₃ + 12O1₂ = Products: H1₂O1 + C1O1₂ + 12O1₂ Carbon, hydrogen, and sulfur are already balanced. There are 13 oxygen atoms on the left side and 13+12=25 on the right. To balance the oxygen we can add 12 more oxygen atoms to the reactants side: C1₈H1₁₈O1₃ + 12O1₂ = H1₂O1 + C1O1₂ + 24O1₂ Now the oxygen atoms are balanced, but we have excess carbon on the products side. The coefficient of CO should be multiplied by 8 to balance the carbon: C1₈H1₁₈O1₃ + 12O1₂ = 9H1₂O1 + 8C1O1₂ + 24O1₂ Now the equation is balanced with coefficients: 1, 12, 9, 8, 24. Choice B is the only one with these coefficients.

Balance the Following Equation: C8H18O3(l) + O2(g) → H2O(g)

Balance the Following Equation: C₈H₁₈O₃(l) + O₂(g) → H₂O(g)