The following output from MINITAB presents the results of a hypothesis test. Test of $m u = 35$ vs. not $= 35$. The assumed standard deviation $9.3$
$\begin{array}{lcccrr}
\mathrm{N} & \text { Mean } & \text { SE Mean } & 95 \% \text { CI } & \text { Z } & \text { P } \
59 & 31.26 & 1.359737 & (1.40462111,6.7347896) & -3.088977 & 0.002009 \
\hline
\end{array}$
What is the value of the test statistic?
A) 0.002009
B) 1.359737
C) -3.088977
D) 31.26

Question

The following output from MINITAB presents the results of a hypothesis test. Test of $m u = 35$ vs. not $= 35$. The assumed standard deviation $9.3$
$\begin{array}{lcccrr}
\mathrm{N} & \text { Mean } & \text { SE Mean } & 95 \% \text { CI } & \text { Z } & \text { P } \
59 & 31.26 & 1.359737 & (1.40462111,6.7347896) & -3.088977 & 0.002009 \
\hline
\end{array}$
 What is the value of the test statistic?
A) 0.002009
B) 1.359737
C) -3.088977
D) 31.26

Quizplus · Accepted Answer

The test statistic is represented by the Z-score, which is -3.088977.

The Following Output from MINITAB Presents the Results of a Hypothesis