The following output from MINITAB presents the results of a hypothesis test. Test of $\mathrm { mu } = 55 \mathrm { vs }$. not $= 55$ The assumed standard deviation $8.1$
$\begin{array}{llccrrr}
\mathrm{N} & \text { Mean } & \text { SE Mean } & 95 \% \mathrm{CI} & \mathrm{Z} & \mathrm{P} \
48 & 52.75 & 1.877561 & (3.93378802,11.2938253) & -1.924501 & 0.054292 \
\hline
\end{array}$
What are the null and alternate hypotheses?

A) $H _ { 0 } : \mu = 55 , H _ { 1 } : \mu = 52.75$
B) $H _ { 0 } : \mu = 52.75 , H _ { 1 } : \mu \neq 52.75$
C) $H _ { 0 } : \mu = 55 , H _ { 1 } : \mu \neq 55$
D) $H _ { 0 } : \mu \neq 55 , H _ { 1 } : \mu = 55$

Question

The following output from MINITAB presents the results of a hypothesis test. Test of $\mathrm { mu } = 55 \mathrm { vs }$. not $= 55$ The assumed standard deviation $8.1$
$\begin{array}{llccrrr}
\mathrm{N} & \text { Mean } & \text { SE Mean } & 95 \% \mathrm{CI} & \mathrm{Z} & \mathrm{P} \
48 & 52.75 & 1.877561 & (3.93378802,11.2938253) & -1.924501 & 0.054292 \
\hline
\end{array}$
 What are the null and alternate hypotheses?

A) $H _ { 0 } : \mu = 55 , H _ { 1 } : \mu = 52.75$
B) $H _ { 0 } : \mu = 52.75 , H _ { 1 } : \mu \neq 52.75$
C) $H _ { 0 } : \mu = 55 , H _ { 1 } : \mu \neq 55$
D) $H _ { 0 } : \mu \neq 55 , H _ { 1 } : \mu = 55$

Quizplus · Accepted Answer

The null hypothesis states that the population mean is equal to 55 and the alternative hypothesis states that the population mean is not equal to 55. This can be seen from the test of $\mathrm { mu } = 55 \mathrm { vs } $ not $= 55$ in the output.

The Following Output from MINITAB Presents the Results of a Hypothesis