Rewrite using the power and product rules. Assume all variables represent positive real numbers.
-$\log _ { 6 } \sqrt { 2 x }$
A) $\log _ { 6 } \sqrt { 2 } + \log _ { 6 } \sqrt { x }$
B) $\frac { 1 } { 2 } \log _ { 6 } 2 + \frac { 1 } { 2 } \log _ { 6 } x$
C) $\frac { 1 } { 2 } \log _ { 6 } 2 x$
D) $\log _ { 6 } 2 + \frac { 1 } { 2 } \log _ { 6 } x$

Question

Quizplus · Accepted Answer

The expression $\log _ { 6 } \sqrt { 2 x }$ can be rewritten using the power rule as $\frac { 1 } { 2 } \log _ { 6 } 2 x$, and then using the product rule, it becomes $\frac { 1 } { 2 } \log _ { 6 } 2 + \frac { 1 } { 2 } \log _ { 6 } x$.

Rewrite Using the Power and Product Rules log⁡62x\log _ { 6 } \sqrt { 2 x }log6​2x​

Rewrite Using the Power and Product Rules $\log _ { 6 } \sqrt { 2 x }$