Factor by grouping.
-$$x ^ { 2 } + 5 x + x + 5$$
A) $( x - 5 ) ( x - 1 )$
B) $( x + 5 ) ( x + 1 )$
C) $( x - 5 ) ( x + 1 )$
D) $( x + 5 ) ( x - 1 )$

Name: Factor by grouping. -\[x ^ { 2 } + 5 x + x + 5\] A) $( x - 5 ) ( x - 1 )$ B) $( x + 5 ) ( x + 1 )$ C) $( x - 5 ) ( x + 1 )$ D) $( x + 5 ) ( x - 1 )$
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Question

Quizplus · Accepted Answer

The given expression can be rewritten as $x^2 + x + 5x + 5$. Factoring by grouping, we get $x(x + 1) + 5(x + 1)$. Factoring out the common factor $(x + 1)$, we get $(x + 5)(x + 1)$.

Factor by Grouping x2+5x+x+5x ^ { 2 } + 5 x + x + 5x2+5x+x+5

Factor by Grouping $x ^ { 2 } + 5 x + x + 5$