Solve.
-The distance that a spring is stretched by a hanging object varies directly as the mass of the object. If an object with a mass of 27 kg stretches a spring 31 cm, find the stretch when the object has a
Mass of 22 kg.
A) 80 cm
B) 25.3 cm
C) 1.1 cm
D) 19.2 cm

Question

Quizplus · Accepted Answer

We can use the formula for direct variation: distance = k * mass, where k is the constant of variation. To find k, we can use the given values: 31 = k * 27. Solving for k, we get k = 31/27. 
Then, we can use the same formula with the new mass value of 22 kg: distance = (31/27) * 22. Simplifying, we get distance = 25.3 cm. Therefore, the answer is B.

Solve. -The Distance That a Spring Is Stretched by a Hanging