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Question 68
Find the missing numerator and denominator.- x2−64x2−10x+25÷??=(x−8) (x+10) 8(x−5) \frac { x ^ { 2 } - 64 } { x ^ { 2 } - 10 x + 25 } \div \frac { ? } { ? } = \frac { ( x - 8 ) ( x + 10 ) } { 8 ( x - 5 ) }x2−10x+25x2−64÷??=8(x−5) (x−8) (x+10)
A) 8x+64x2+5x−50\frac { 8 x + 64 } { x ^ { 2 } + 5 x - 50 }x2+5x−508x+64 B) x−5(x−8) (x+10) \frac { x - 5 } { ( x - 8 ) ( x + 10 ) }(x−8) (x+10) x−5 C) (x−8) (x+10) x−5\frac { ( x - 8 ) ( x + 10 ) } { x - 5 }x−5(x−8) (x+10) D) 8x−64x2+5x−50\frac { 8 x - 64 } { x ^ { 2 } + 5 x - 50 }x2+5x−508x−64
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Q71: Divide.- Q72: Divide.- Q73: Divide.- Unlock this Answer For Free Now!View this answer and more for free by performing one of the following actionsScan the QR code to install the App and get 2 free unlocksMaximize QR codeUnlock quizzes for free by uploading documentsUpload documents
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