Find the missing numerator and denominator.
-$$\frac { 36 x ^ { 2 } - 25 } { x ^ { 2 } - 4 } \div \frac { ? } { ? } = \frac { 6 x - 5 } { x - 2 }$$
A) $\frac { 6 x + 5 } { x + 2 }$

B) $\frac { ( 6 x + 5 ) \left( 36 x ^ { 2 } - 25 \right) } { \left( x ^ { 2 } + 2 \right) ( x + 2 ) }$

C) $\frac { x - 2 } { 6 x - 5 }$

D) $\frac { 6 x - 5 } { x - 2 }$

Question

Find the missing numerator and denominator.
-$$\frac { 36 x ^ { 2 } - 25 } { x ^ { 2 } - 4 } \div \frac { ? } { ? } = \frac { 6 x - 5 } { x - 2 }$$
A) $\frac { 6 x + 5 } { x + 2 }$

B) $\frac { ( 6 x + 5 ) \left( 36 x ^ { 2 } - 25 \right) } { \left( x ^ { 2 } + 2 \right) ( x + 2 ) }$

C) $\frac { x - 2 } { 6 x - 5 }$

D) $\frac { 6 x - 5 } { x - 2 }$

Quizplus · Accepted Answer

The division by a fraction is equivalent to multiplying by its reciprocal. Therefore, the missing fraction must be the reciprocal of the right side of the equation, which is $\frac{6x+5}{x+2}$, making option A correct.

Find the Missing Numerator and Denominator 36x2−25x2−4÷??=6x−5x−2\frac { 36 x ^ { 2 } - 25 } { x ^ { 2 } - 4 } \div \frac { ? } { ? } = \frac { 6 x - 5 } { x - 2 }x2−436x2−25​÷??​=x−26x−5​

Find the Missing Numerator and Denominator $\frac { 36 x ^ { 2 } - 25 } { x ^ { 2 } - 4 } \div \frac { ? } { ? } = \frac { 6 x - 5 } { x - 2 }$