Solve the problem.
-The formula $\mathrm { A } = 291 \mathrm { e } ^ { 0.024 \mathrm { t } }$ models the population of a particular city, in thousands, $\mathrm { t }$ years after 1998 . When will the population of the city reach 353 thousand?
A) 2006
B) 2007
C) 2008
D) 2009

Question

Quizplus · Accepted Answer

The population of the city will reach 353 thousand when $ 291 \mathrm { e } ^ { 0.024 \mathrm { t } } = 353 $. Solving for $ t $ gives $ t = \frac { \ln ( 353 / 291 ) } { 0.024 } \approx 8 $. Since $ t $ represents the number of years after 1998, the population of the city will reach 353 thousand in 1998 + 8 = 2006.

Solve the Problem A=291e0.024t\mathrm { A } = 291 \mathrm { e } ^ { 0.024 \mathrm { t } }A=291e0.024t

Solve the Problem $\mathrm { A } = 291 \mathrm { e } ^ { 0.024 \mathrm { t } }$