Solve for t or y, as appropriate.
-$$\ln ( y - 6 ) - \ln 10 = x + \ln x$$
A) $e ^ { x } + 10 x + 6$
B) $10 x e ^ { x } + 6$
C) $2 x + 16$
D) $( x + 10 ) \mathrm { e } ^ { x } + 6$

Question

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The Answer of Solve for t or y, as appropriate.
-$$\ln ( y - 6 ) - \ln 10 = x + \ln x$$
A) $e ^ { x } + 10 x + 6$
B) $10 x e ^ { x } + 6$
C) $2 x + 16$
D) $( x + 10 ) \mathrm { e } ^ { x } + 6$

Solve for T or Y, as Appropriate ln⁡(y−6)−ln⁡10=x+ln⁡x\ln ( y - 6 ) - \ln 10 = x + \ln xln(y−6)−ln10=x+lnx

Solve for T or Y, as Appropriate $\ln ( y - 6 ) - \ln 10 = x + \ln x$