Find the domain and range for the indicated function.
-$f ( x ) = 2 , \quad g ( x ) = 2 + \sqrt { x } ; \quad f / g$
A) D: $x \geq 0$
R: $y \leq 1$

B) D: $x \geq 0$
R: $y \leq 2$

C) D: $x \geq - 2$
R: $\mathrm { y } \geq 0$

D) D: $x \geq 0$
R: $\mathrm { y } \geq 1$

Question

Find the domain and range for the indicated function.
-$f ( x ) = 2 , \quad g ( x ) = 2 + \sqrt { x } ; \quad f / g$
A) D: $x \geq 0$
R: $y \leq 1$

B) D: $x \geq 0$
R: $y \leq 2$

C) D: $x \geq - 2$
R: $\mathrm { y } \geq 0$

D) D: $x \geq 0$
R: $\mathrm { y } \geq 1$

Quizplus · Accepted Answer

The domain of $f/g$ is $x \geq 0$ because the square root function $g(x) = 2 + \sqrt{x}$ requires $x$ to be non-negative. The range is $y \leq 1$ because $f(x) = 2$ is a constant function and when divided by $g(x)$, the result will always be less than or equal to 1 for $x \geq 0$.

Find the Domain and Range for the Indicated Function f(x)=2,g(x)=2+x;f/gf ( x ) = 2 , \quad g ( x ) = 2 + \sqrt { x } ; \quad f / gf(x)=2,g(x)=2+x​;f/g

Find the Domain and Range for the Indicated Function $f ( x ) = 2 , \quad g ( x ) = 2 + \sqrt { x } ; \quad f / g$