Determine if the function is even, odd, or neither.
-$$h ( t ) = \sqrt { t ^ { 2 } - 6 }$$
A) Even
B) Odd
C) Neither

Name: Determine if the function is even, odd, or neither. -\[h ( t ) = \sqrt { t ^ { 2 } - 6 }\] A) Even B) Odd C) Neither
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Question

Quizplus · Accepted Answer

A function is even if $f(-x) = f(x)$ for all $x$ in the function's domain. For $h(t) = \sqrt{t^2 - 6}$, replacing $t$ with $-t$ gives $h(-t) = \sqrt{(-t)^2 - 6} = \sqrt{t^2 - 6}$, which is equal to $h(t)$. Therefore, $h(t)$ is even.

Determine If the Function Is Even, Odd, or Neither h(t)=t2−6h ( t ) = \sqrt { t ^ { 2 } - 6 }h(t)=t2−6​

Determine If the Function Is Even, Odd, or Neither $h ( t ) = \sqrt { t ^ { 2 } - 6 }$