Find the first three nonzero terms of the Maclaurin series for the given function and the values of x for which the series
converges absolutely.
-$$f ( x ) = \cos x - \frac { 3 } { 1 - x }$$
A) $- 2 + 3 x + \frac { 7 } { 2 } x ^ { 2 } + \ldots , - 1

Question

Find the first three nonzero terms of the Maclaurin series for the given function and the values of x for which the series
converges absolutely.
-$$f ( x ) = \cos x - \frac { 3 } { 1 - x }$$
A) $- 2 + 3 x + \frac { 7 } { 2 } x ^ { 2 } + \ldots , - 1 < x < 1$
B) $- 2 - 3 x - \frac { 7 } { 2 } x ^ { 2 } - \ldots , - 1 < x < 1$
C) $- 2 - 3 x + \frac { 7 } { 2 } x ^ { 2 } - \ldots , - 1 < x < 1$
D) $- 2 - x - \frac { 7 } { 2 } x ^ { 2 } - \ldots , - 1 < x < 1$

Quizplus · Accepted Answer

The Answer of Find the first three nonzero terms of the Maclaurin series for the given function and the values of x for which the series
converges absolutely.
-$$f ( x ) = \cos x - \frac { 3 } { 1 - x }$$
A) $- 2 + 3 x + \frac { 7 } { 2 } x ^ { 2 } + \ldots , - 1 < x < 1$
B) $- 2 - 3 x - \frac { 7 } { 2 } x ^ { 2 } - \ldots , - 1 < x < 1$
C) $- 2 - 3 x + \frac { 7 } { 2 } x ^ { 2 } - \ldots , - 1 < x < 1$
D) $- 2 - x - \frac { 7 } { 2 } x ^ { 2 } - \ldots , - 1 < x < 1$

Find the First Three Nonzero Terms of the Maclaurin Series f(x)=cos⁡x−31−xf ( x ) = \cos x - \frac { 3 } { 1 - x }f(x)=cosx−1−x3​

Find the First Three Nonzero Terms of the Maclaurin Series $f ( x ) = \cos x - \frac { 3 } { 1 - x }$