Find the linearization of the function at the given point.
-$f ( x , y ) = 3 \sin x - 8 \cos y$ at $\left( 0 , \frac { \pi } { 2 } \right)$
A) $L ( x , y ) = - 3 x + 8 y - 4 \pi$
B) $L ( x , y ) = - 3 x - 8 y - 4 \pi$
C) $L ( x , y ) = 3 x - 8 y - 4 \pi$
D) $\mathrm { L } ( \mathrm { x } , \mathrm { y } ) = 3 \mathrm { x } + 8 \mathrm { y } - 4 \pi$

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The Answer of Find the linearization of the function at the given point.
-$f ( x , y ) = 3 \sin x - 8 \cos y$ at $\left( 0 , \frac { \pi } { 2 } \right)$
A) $L ( x , y ) = - 3 x + 8 y - 4 \pi$
B) $L ( x , y ) = - 3 x - 8 y - 4 \pi$
C) $L ( x , y ) = 3 x - 8 y - 4 \pi$
D) $\mathrm { L } ( \mathrm { x } , \mathrm { y } ) = 3 \mathrm { x } + 8 \mathrm { y } - 4 \pi$

Find the Linearization of the Function at the Given Point f(x,y)=3sin⁡x−8cos⁡yf ( x , y ) = 3 \sin x - 8 \cos yf(x,y)=3sinx−8cosy

Find the Linearization of the Function at the Given Point $f ( x , y ) = 3 \sin x - 8 \cos y$